molad-solad calendar RE: Brij Tithi Re: Correction 0.5 Day (not Tithi) Re: ...

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molad-solad calendar RE: Brij Tithi Re: Correction 0.5 Day (not Tithi) Re: ...

Karl Palmen

Dear Brij & Calendar People

 

I suggested the molad as part of a calendar that implements Brij’s calculation

(448*365.2421875 + 0.5)/5541  = 29.530590146… days = 29d 12h 44m 2.9886302…. s.

in a calendar. It involved not only a molad of interval 29 + 2940/5541 days as shown by Brij, but also a solar molad, which I referred to as a solad with interval 365.2421875 days.

The first day of a year is the day of the first molad on or after the solad of the year.

 

I forgot that 5541 is divisible by three and so the molad interval simplifies to 29 + 980/1847 days.

 

This makes 448 calendar years normally equal to 5541 months of 163629 days, but sometimes the 448 calendar years have just 5540 months to bring the mean year down to 365.2421875 days from about 365.2433… days that would otherwise occur.

5541 months is half a day longer the 448 mean years. This half day does indeed raise the tithi from 1 338/326919 days to 1 339/326919 days = 1 113/108973 days, but the tithi is not necessary for this calendar.

 

 

I have considered molad-solad calendars before. While they are very simple to specify, they are not so simple to use in practice.

One could for example have molad interval of 29.53059 days and solad interval of 365.24220 days.

 

Karl

 

16(10(11

 

From: Brij Bhushan metric VIJ [mailto:[hidden email]]
Sent: 02 June 2017 22:25
To: Palmen, Karl (STFC,RAL,ISIS); [hidden email]
Cc: Brij Bhushan metric VIJ Ex-Flt.Lt. Indian Air Force
Subject: Brij Tithi Re: Correction 0.5 Day (not Tithi) Re: Thanks Re: Not Sure Re: Re-verifying Re: Correction to 448-year cycle RE: The Best option Re: 19-years/7 Leap months Re: ...

 

Karl, sirs:

Karl suggested to increase lunar length, Molad, to:

>So let’s have a molad whose interval is >exactly: 163629/5541 days = 

>29 <a href="tel:&#43;%202940/5541">+ 2940/5541 days.

>The first day of each month occurs on the >day of a its molad.

     This may change the value of my "used Tithi=1 338/326919 day"; to 1 339/336919 day; as earlier also shown by Karl - during his checking upon my results. He had the 'right to twist my mind, sirs'. 

I recall having pointed to such correction, in my attached hand worked calculation!

However, I reproduce my re-worked figures:

image1.JPG

     The point, not becoming clearer by me (due language) was, the last Tithi in 5541st moon i.e. 163460th in 448-years; instead of "half Tithi needed to be increased (by 0.5 day) to 1.000516947623112 day", so the completed 5541th moon, and 448-years would give Mean Lunation=163629/5541 i.e. 

29d12h44m2s.98863.

     The above 'photo' shall obviously clear this, I hope. 

Regards,

Ex-FltLt Brij Bhushan VIJ, Author

Brij-Gregorian Modified calendar

Friday, 2017 June 02H14:39 (decimal)

 

Sent from my iPhone


On Jun 2, 2017, at 2:07 AM, "[hidden email]" <[hidden email]> wrote:

So let’s have a molad whose interval is exactly

163629/5541 days = 29 + 2940/5541 days.

The first day of each month occurs on the day of a its molad.

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Mean Lunation & Tithi Re: molad-solad calendar RE: Brij Tithi Re: Correction 0.5 Day (not Tithi) Re: ...

Brij Bhushan metric VIJ
Karl, Walter list sirs:
I was pondering over a little further; if or not I could bring the value of Mean Lunation to almost the current value of Moon/Lunar cycle (Lunation).

>5541 months is half a day longer the 448 >mean years. This half day does indeed >raise the tithi from <a href="tel:1%20338/326919" dir="ltr" x-apple-data-detectors="true" x-apple-data-detectors-type="telephone" x-apple-data-detectors-result="4">1 338/326919 days to <a href="tel:1%20339/326919" dir="ltr" x-apple-data-detectors="true" x-apple-data-detectors-type="telephone" x-apple-data-detectors-result="5">1 >339/326919 days = <a href="tel:1%20113/108973" dir="ltr" x-apple-data-detectors="true" x-apple-data-detectors-type="telephone" x-apple-data-detectors-result="6">1 113/108973days, but >the tithi is not necessary for this calendar.

I have considered molad-solad calendars before. While they are very simple to specify, they are not so simple to use in practice.

>One could for example have molad interval >of 29.53059 days and solad interval of >365.24220 days.

 I wonder, if Karl has noticed that the increment I make in 30th 'tithi' of 5541st moon is of (0.49276126 day); slightly lesser than half day!

image1.JPG

If I did this 'similar' adding of (0.49276126 day) also at 2771st moon, my obtained result is: 163628.9850055724 days/5541 moons to give Mean Lunation=29d12h44m2s.7548 24; as against the actual lunar Moon of 29.53058886 days, short of only 0s.123422.

 I do not under estimate Karl's pointing to my "NOT changing the value of definition of the TITHI=no.of days in 896-years/no.of (11082*29 1/2)=326919 Tithi in 11082 moons". This is what I pointed to 'attempting to change' Tithi value! 

I am sure 'even' with addition of about half day during 2771st & 5541st moons, 30th Tithi during these months shall remain lesser than, my Tithi value of 1 338/326919 day, and Mean Year & Mean Lunation also remain same, sir!

Regards,

Ex-Flt Lt Brij Bhushan VIJ, Author

Brij-Gregorian Modified Calendar 

Monday, 2017 June 05H06:17 (decimal)


Sent from my iPhone

On Jun 5, 2017, at 5:17 AM, "[hidden email]" <[hidden email]> wrote:

5541 months is half a day longer the 448 mean years. This half day does indeed raise the tithi from 1 338/326919 days to 1 339/326919 days = 1 113/108973 days, but the tithi is not necessary for this calendar.

 

 

I have considered molad-solad calendars before. While they are very simple to specify, they are not so simple to use in practice.

One could for example have molad interval of 29.53059 days and solad interval of 365.24220 days.


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