Dear Calendar People
I found that the years that have a leap week (week 53) in the ISO week numbering can be constructed by having five of these years in each row, except when a leap year needs to be dropped one simply places the words 'drop leap year' in three year places. Each full row of five years corresponds to a 28year cycle. Each row with 'drop leap year' corresponds to 12 years. Then having made one full row: 1987 1992 1998 2004 2009 one can easily make the other rows: 1807 1812 1818 1824 1829 1835 1840 1846 1852 1857 1863 1868 1874 1880 1885 1891 1896 drop leap year 1903 1908 1914 1920 1925 1931 1936 1942 1948 1953 1959 1964 1970 1976 1981 1987 1992 1998 2004 2009 2015 2020 2026 2032 2037 2043 2048 2054 2060 2065 2071 2076 2082 2088 2093 2099 drop leap year 2105 2111 2116 2122 2128 2133 2139 2144 2150 2156 2161 2167 2172 2178 2184 2189 2195 drop leap year 2201 and so on every 400 years. Also, I've put the only leap week year of the 28yearcycle whose number is even but not divisible by four in the middle of its row to make each row symmetrical. Karl 07(15(19 
Karl, sir: While I may not argue to use my *divide by six(6) rule using 896yr/159 LWks or 834yr/148 LWks scheme*'; my observation against ISO LWks following is that this is NOT as simple as
just divide by six(6) 'like our earlier divide by four(4) year to insert a Leap Day'.

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