Dear Brij and Calendar People
I was confused too. Brij said: " six moons are added but ONCE every 3 years". That is equivalent to adding two moons every year and so adding 38 NOT 6 moons to each 19year cycle. Now I think Brij really means: " six moons are added ONE MOON every 3 years within each 19year cycle. These could be added to the 3rd, 6th, 9th, 12th, 15th and 18th year of each 19year cycle. Brij later attempts to count the years: "5541 moons over 23 19year cycles i.e. (23*241)2 moons smoothly distributed in [19*23.578947367]years or (437*11)years." I don't understand this. Where does the 23.578947367 come from? Also 437*11 = 4807 years! If each of the six moons were actually added to a year, then there would be 23*19 = 437 years in the 448year cycle, which is 11 years too few! Why not instead take the 6*23 = 138 moons added to the 23 Metonic cycles and put them into the 11 missing years and remove the 2 surplus moons to leave 136 moons. Then we have 11 years with 4 leap months (136  11*12 = 4). This is the same as a 24th Metonic cycle with an Octaeteris removed as I suggested earlier. Karl 16(08(07 Original Message From: East Carolina University Calendar discussion List [mailto:[hidden email]] On Behalf Of Brij Bhushan metric VIJ Sent: 01 April 2017 03:39 To: [hidden email] Subject: Confusion Re: Patterns Re: Short & simple Re: (235+6Adhika) Re: 13th removed from all but 1 in 13 months RE: FORMAT Fwd: ... Karl, sirs: >Brij's suggestion is to add 6 months to >each of 23 19year cycles then remove 2 >months. Only the months tally >Months: 23*(235+6)  2 = 5541 I think, this is yet another, confusion! The point I made was for {23*(235+6)2= 5541} Lunations to be counted. Since 19years have 235 moons; six moons are added but ONCE every 3 years  thus making for 23x241=5543 and TWO removed once at [12*241]1; and then at [11*241]1 creating uniform distribution of {2892+2651} =5541 moons; on adding ONE once every 3years in 19year cycle of (235+6) moons! This make {[12*(235+6)1}+{(11*235+6)1}= 5541 moons over 23 19year cycles i.e. (23*241)2 moons smoothly distributed in [19*23.578947367]years or (437*11)years. I expect this make distribution clear, sir. Regards, Brij Bhushan metric VIJ, Author BrijGregorian Modified calendar Friday, 2017 March 31H19:59 (decimal) Sent from my iPhone > On Mar 31, 2017, at 8:32 AM, Karl Palmen <[hidden email]> wrote: > > Dear Brij and Calendar People > > Brij says that has target is the Mean Year and Mean Month, therefore BOTH years and months must be counted. > > One moon removed from (235+6) in 19year cycle etc. does NOT count YEARS. > Also, this has no pattern of YEARS with leap months, because the YEARS are not counted. > > Karl > > 16(08(04 > > Original Message > From: East Carolina University Calendar discussion List [mailto:[hidden email]] On Behalf Of Brij Bhushan metric VIJ > Sent: 31 March 2017 15:19 > To: [hidden email] > Subject: Patterns Re: Short & simple Re: (235+6Adhika) Re: 13th removed from all but 1 in 13 months RE: FORMAT Fwd: ... > > Karl, list sirs: >> Also if the years with a leap month were >spread as smoothly as possible, they will >naturally form a pattern of 24 19year >cycles one of which have an Octaeteris >removed. > I thank you. I, however, leave the choice to astronomers  the need of patternimportance. My target was for Mean Year & Mean Lunation. > One moon removed from (235+6) in 19year cycle; once every 3years also is uniform distribution, I suppose sir. > Regards & thanks, > Brij zbhushan metric VIJ, Author > BrijGregorian Modified calendar > Friday, 2017 March 31H07:31 (decimal) > > Sent from my iPhone > >> On Mar 31, 2017, at 5:23 AM, Karl Palmen <[hidden email]> wrote: >> >> Also if the years with a leap month were spread as smoothly as possible, they will naturally form a pattern of 24 19year cycles one of which have an Octaeteris removed. 
Karl,list sirs:
>I don't understand this. Where does the >23.578947367 come from? >Also 437*11 = 4807 years! It is unfortunate, I have thick fingers; which occasionally cause the slips. 448years are (448/19=23.578947367 Nineteen (19)year cycles! And, 437+11=448years [and not 437*11  my finger problem, possibly]. Now moon count: [(12x19years)+(11x19years)+(0.578947367x19years)]=228+209+11 make up the 448years/ having 5541 moons. The two moons removed are from the additional moons  one each at end of 12th nineteen years & the other at end of 11th nineteenth year cycle. Each 19year cycle has 235 moons (12x19 plus one each during 3rd, 5th, 8th, 11th, 14th, 17th & 19th years i.e. Making 228+7=235 moons per 19years. I further ADD 6moons during 1st, 4th, 7th, 10th, 13th & 16th years i.e. Once every 3years. Thus making a total of 235+6=241 per 19years. In 23.578947367 nineteen(19) Year cycles (on deleting 2 as suggested), we have the total 5543  2=5541 moons in 448years. There must've been other combinations, I do. It deny, sir! I think this to be simpler scheme. I have heard of ADHIK (added) moons in Hindu calendars. These are considered auspicious/ good for festivities also. But, I have no idea of their rules. My point was their coordination with moons & years exist! These are 23cycles of 19years PLUS 11years catering to 448years/5541 Lunation resulting in the right Mean Year value, I provided, in my previous posts. I expect this to be in order, sir. It is likely this or such an arrangement was in use by Harappan culture, but Harappa calendar so far is a mystery. Regards, Brij Bhushan metric VIJ, Author BrijGregorian Modified calendar Monday, 2017 April 02H22:21 (decimal) Sent from my iPhone > On Apr 3, 2017, at 8:24 AM, Karl Palmen <[hidden email]> wrote: > > I don't understand this. Where does the 23.578947367 come from? > Also 437*11 = 4807 years! 
Dear Brij and Calendar People
Brij describes a calendar and according to the description of the calendar, it has 5541 moons in 437 years. Brij assumes it has 448 years before 'counting' them. I don't think Brij has a clear idea what a year is in the calendar he has suggested. Original Message From: East Carolina University Calendar discussion List [mailto:[hidden email]] On Behalf Of Brij Bhushan metric VIJ Sent: 04 April 2017 06:13 To: [hidden email] Subject: Re: Confusion Re: Patterns Re: Short & simple Re: (235+6Adhika) Re: ... Karl,list sirs: >I don't understand this. Where does the >23.578947367 come from? >Also 437*11 = 4807 years! It is unfortunate, I have thick fingers; which occasionally cause the slips. 448years are (448/19=23.578947367 Nineteen (19)year cycles! And, 437+11=448years [and not 437*11  my finger problem, possibly]. Now moon count: [(12x19years)+(11x19years)+(0.578947367x19years)]=228+209+11 make up the 448years/ having 5541 moons. KARL REPLIES: Thank you for Brij for explaining this. But this is NOT a COUNT of the years, because the result of the count (448) is assumed beforehand to work out the 23.578947367 and the 11. BRIJ CONTINUES WITH A DESCRIPTION OF THE CALENDAR: The two moons removed are from the additional moons  one each at end of 12th nineteen years & the other at end of 11th nineteenth year cycle. Each 19year cycle has 235 moons (12x19 plus one each during 3rd, 5th, 8th, 11th, 14th, 17th & 19th years i.e. Making 228+7=235 moons per 19years. I further ADD 6moons during 1st, 4th, 7th, 10th, 13th & 16th years i.e. Once every 3years. BRIJ THEN MAKES A CONCLUSION: Thus making a total of 235+6=241 per 19years. In 23.578947367 nineteen(19) Year cycles (on deleting 2 as suggested), we have the total 5543  2=5541 moons in 448years. KARL REPLIES: But we have exactly 23 (not 23.578946367) 19year cycles and so 437 years. This makes the mean year about 5541/437 = 12.6796... moons and so about 374.437... days. I don't see any mention of a (0.578946367) 19year cycle of 11 years in the description. I can now guess the missing part of the description: "The resulting 23 19year cycles are followed by 11 years with no moons making 11/19 = 0.578946367 of a 19year cycle." If this were added to the description, the conclusion following it would be correct. BRIJ CONTINUES: There must've been other combinations, I do. It deny, sir! I think this to be simpler scheme. I have heard of ADHIK (added) moons in Hindu calendars. These are considered auspicious/ good for festivities also. But, I have no idea of their rules. My point was their coordination with moons & years exist! These are 23cycles of 19years PLUS 11years catering to 448years/5541 Lunation resulting in the right Mean Year value, I provided, in my previous posts. I expect this to be in order, sir. It is likely this or such an arrangement was in use by Harappan culture, but Harappa calendar so far is a mystery. KARL REPLIES: I don't know much about Hindu calendars, but I found out that the ADHIK months are simply the leap months added to a year of 12 months or rarely 11 months. See https://en.wikipedia.org/wiki/Adhik_Maas Also I don't think Brij's suggestion is simpler than my suggestion of adding 11 years of 136 moons. These 11 years can be the same as the first 11 years of a 19year cycle. Years: 23*19 + 11 = 448 Moons: 23*235 + 136 = 5541. Also my suggestion is flexible. 23 does not have to be the number of 19year cycles one adds the 11 years to. For more accuracy, a number less than 23 is needed, for example 17 which leads to Years: 17*19 + 11 = 334 Moons: 17*235 + 136 = 4131. What I do know about the Hindu calendar is that the name of each lunar month is defined by which sign of the Hindu sidereal zodiac the sun enters in that month. Sometimes a lunar month occurs in which the sun does not enter a sign of the zodiac. Such a month is an ADHIK month. This is mentioned in the link I gave to Adhik Maas. I'd expect the resulting years of 13 months would follow a pattern similar to what I suggested of 19year cycles occasionally cut to 11 years. Also I'm curious about why Brij chose the 3rd, 5th, 8th, 11th, 14th, 17th & 19th years, even though the 3rd, 6th, 8th, 11th, 14th, 17th & 19th years as used in the Hebrew calendar would work and unlike Brij's 7 years are spaced as smoothly as possible. Perhaps, it was another slip of the thick fingers. Karl 16(08(08 Tuesday Ace of Diamonds, ISOweek deck Regards, Brij Bhushan metric VIJ, Author BrijGregorian Modified calendar Monday, 2017 April 02H22:21 (decimal) Sent from my iPhone > On Apr 3, 2017, at 8:24 AM, Karl Palmen <[hidden email]> wrote: > > I don't understand this. Where does the 23.578947367 come from? > Also 437*11 = 4807 years! 
Karl, list sirs:
>I can now guess the missing part of the description:
>"The resulting 23 19year cycles are >followed by 11 years with no moons making ><a href="xappledatadetectors://5" dir="ltr" xappledatadetectors="true" xappledatadetectorstype="calendarevent" xappledatadetectorsresult="5" style="webkittextdecorationcolor: rgba(0, 0, 0, 0.258824);">11/19 = 0.578946367 of a 19year cycle." >If this were added to the description, the >conclusion following it would be correct. I thank you, Karl for 'explaining the jumbled jigsaw, with your Astromathematical expertise'. I have only tried to use the exactness of 19year Harappa cycle, I believed, could be used counting (437+11)years to count 5541moons
in (896/2=448years).
19year cycle, as you know, may have 235moons/6932 1/2 Tithi; each Tithi of 1 338/326919 day in my 896years with Mean Year=365.2421875 days; and (with an EXTRA tithi) getting Mean Lunation=(327257
+1) days/326919 Tithi=29d 12h 44m 2s.9887. Be kind to reconcile that 896year cycle is a complete lunisolar cycle!
Regards,
Brij Bhushan metric VIJ, Author
BrijGregorian Midified calendar
Tuesday, 2017 April 04H09:94 (decimal)
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Resending this mail, returned by server since from my [hidden email] account.
Brij Bhushan metric VIJ
Tuesday, 2017 April 04H13:51 (decimal)
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