Dear Brij and Calendar People I see Brij attempts to link the 19year cycle of 235 months to his 896year cycle, but do not see what use it would be in constructing a calendar.
Instead, one can take 24 19year cycles remove one octaeteris of 8 years and of 99 months and we get the 448year cycle of 5541 months exactly (no 2 month difference).
24*19 – 8 = 448 and 24*235 – 99 = 5541. This is half an 896year cycle. I do see that Brij adds one day to the 11082 lunar months of this 896year cycle to make it more accurate. Then the lunar months will drift one day later with
respect to the solar calendar once every 896 years. Yesterday I thought of the possibility of adding one 13^{th} back to the 896year cycle to do this correction, in the removing of the 13^{th}s
idea (so 853 rather than 852 months have a 13^{th}). The leap months would occur slightly less often, because each takes its days from the 13^{th}s removed from most of the other months. In 26880 years 30 13^{th}s are added back and
so there is one less leap month. This leads to the 26880year cycle I’ve mention before and is listed in http://thelight.com/cal/Lunisolar128.html
It has a mean lunation of 29.5305887… days, which is slightly less than the 29.5305901…. days Brij gets, because the leap month removed has 30 days while a
mean month has few days. Karl 16(08(03 From: East Carolina University Calendar discussion List [mailto:[hidden email]]
On Behalf Of Brij Bhushan metric VIJ Dear Karl, list sirs: >Brij’s 896year cycle of 11082 months has ><a href="tel:11082%20%2012">11082 – 12*896 = 330 leap months and so >10230 months have a 13^{th} removed and so ><a href="tel:11082%20%2010230">11082 – 10230 = 852 month keep
the 13^{th}. >This works out is 1 in 13.00704… months. >For the more accurate 334year cycle we >get 4131 – 31*123 = 318 months that keep >the 13^{th}, which is 1 in 12.99057… months.
I thank you, and the list for reelavuating my calculations; but I stand put with my 'tithi' value of: No.of days in 896/years/No.of Tithi in (11082x29 1/2) or 326919=1 338/326919 day. This
fits in 896years, 834years & my 19years 'harappatithi' cycles. "896years have 327257 days in 11082 moons but ONE day/Tithi of 1 338/326819 day short. Adding 'this' ONE added/ 'Adhika day' in the cycle result
in Mean Lunation={(327257+1)/ 326919) =29.530590146183 days} i.e.29d 12h 44m 2s.9887. This cycle may have (2x448)years of (2x5541) moons; accounted as [(12*241) 1]+[(11*241)1]= 2891+2650= 5541 moons to give the right (above)
Mean Lunation. The ERA may start at the beginning of Kali Era on 3102BCE making the year, Y2018=5120th or the last year of (40th*128year)
cycles. This may be Noted, that 19years have 235 moons BUT adding "six(6) Kshamoons to be deleted ONCE every 3years " make
the required (2416= 235) moons per 19year cycle. Thus, [(12*241)1+(11*241)1]; are {(2x5543)2} ie (23x241) moons per 448years [23*241 =5543 lunation]. This produces Mean Lunation of 29d 12h 44m 2s.9887 in comparison to the current moon duration. Regards, Brij Bhushan metric VIJ, Author, BrijGregorian Modified calendar Wednesday, 2017 March 29H14:11 (decimal) Sent from my iPhone

Karl, list sirs:
> Yesterday I thought of the possibility of >adding one 13thback to the 896year cycle >to do this correction, in the removing of the >13th's idea (so 853 rather than 852 months >have a 13th). I thank you 😊, Karl for pointing to yet another 'combination'; but I have tried to remain with the simple option at deriving my results. Your providing 'impediments' have always stressed my mind to TRY for simpler solutions. I recall your providing me the alternate 'tithi' value of 1 339/326918 day, also desired if I had my calculation in the right direction  so I stay put with my "corrected/established" value of 1 338/326919 day value, getting result of Mean Lunation=29d 12h 44m 2s.9887 on adding ONE day/Tithi for "Selfconsumed" Lunation over a cycle of precession. I keep high regards for your 'critical anticipation' in probing my mental activity, sir. You may agree removing TWO moons, as shown is simpler than removing 99moons in 8years. Considering "one Kshamoon" once every 3years is simpler. Regards, BrijBhushan metric VIJ, Author BrijModified Gregorian calendar Thursday, 2017 March 30H09:31 (decimal) Sent from my iPhone > On Mar 30, 2017, at 5:08 AM, Karl Palmen <[hidden email]> wrote: > > Yesterday I thought of the possibility of adding one 13th back to the 896year cycle to do this correction, in the removing of the 13ths idea (so 853 rather than 852 months have a 13th). 
Dear Brij and Calendar People
The advantage of subtraction the Octaeteris from the 19year cycle is that BOTH the years and months tally as shown in the calculation Years: 24*19  8 = 448 Months: 24*235  99 = 5541 Also if the years with a leap month were spread as smoothly as possible, they will naturally form a pattern of 24 19year cycles one of which have an Octaeteris removed. Brij's suggestion is to add 6 months to each of 23 19year cycles then remove 2 months. Only the months tally Months: 23*(253+6)  2 = 5541 Karl 16(08(04 Original Message From: East Carolina University Calendar discussion List [mailto:[hidden email]] On Behalf Of Brij Bhushan metric VIJ Sent: 30 March 2017 17:20 To: [hidden email] Subject: Short & simple Re: (235+6Adhika) Re: 13th removed from all but 1 in 13 months RE: FORMAT Fwd: ... Karl, list sirs: > Yesterday I thought of the possibility of >adding one 13thback to the 896year cycle >to do this correction, in the removing of the >13th's idea (so 853 rather than 852 months >have a 13th). I thank you 😊, Karl for pointing to yet another 'combination'; but I have tried to remain with the simple option at deriving my results. Your providing 'impediments' have always stressed my mind to TRY for simpler solutions. I recall your providing me the alternate 'tithi' value of 1 339/326918 day, also desired if I had my calculation in the right direction  so I stay put with my "corrected/established" value of 1 338/326919 day value, getting result of Mean Lunation=29d 12h 44m 2s.9887 on adding ONE day/Tithi for "Selfconsumed" Lunation over a cycle of precession. I keep high regards for your 'critical anticipation' in probing my mental activity, sir. You may agree removing TWO moons, as shown is simpler than removing 99moons in 8years. Considering "one Kshamoon" once every 3years is simpler. Regards, BrijBhushan metric VIJ, Author BrijModified Gregorian calendar Thursday, 2017 March 30H09:31 (decimal) Sent from my iPhone > On Mar 30, 2017, at 5:08 AM, Karl Palmen <[hidden email]> wrote: > > Yesterday I thought of the possibility of adding one 13th back to the 896year cycle to do this correction, in the removing of the 13ths idea (so 853 rather than 852 months have a 13th). 
Karl, list sirs:
>Also if the years with a leap month were >spread as smoothly as possible, they will >naturally form a pattern of 24 19year >cycles one of which have an Octaeteris >removed. I thank you. I, however, leave the choice to astronomers  the need of patternimportance. My target was for Mean Year & Mean Lunation. One moon removed from (235+6) in 19year cycle; once every 3years also is uniform distribution, I suppose sir. Regards & thanks, Brij zbhushan metric VIJ, Author BrijGregorian Modified calendar Friday, 2017 March 31H07:31 (decimal) Sent from my iPhone > On Mar 31, 2017, at 5:23 AM, Karl Palmen <[hidden email]> wrote: > > Also if the years with a leap month were spread as smoothly as possible, they will naturally form a pattern of 24 19year cycles one of which have an Octaeteris removed. 
Dear Brij and Calendar People
Brij says that has target is the Mean Year and Mean Month, therefore BOTH years and months must be counted. One moon removed from (235+6) in 19year cycle etc. does NOT count YEARS. Also, this has no pattern of YEARS with leap months, because the YEARS are not counted. Karl 16(08(04 Original Message From: East Carolina University Calendar discussion List [mailto:[hidden email]] On Behalf Of Brij Bhushan metric VIJ Sent: 31 March 2017 15:19 To: [hidden email] Subject: Patterns Re: Short & simple Re: (235+6Adhika) Re: 13th removed from all but 1 in 13 months RE: FORMAT Fwd: ... Karl, list sirs: >Also if the years with a leap month were >spread as smoothly as possible, they will >naturally form a pattern of 24 19year >cycles one of which have an Octaeteris >removed. I thank you. I, however, leave the choice to astronomers  the need of patternimportance. My target was for Mean Year & Mean Lunation. One moon removed from (235+6) in 19year cycle; once every 3years also is uniform distribution, I suppose sir. Regards & thanks, Brij zbhushan metric VIJ, Author BrijGregorian Modified calendar Friday, 2017 March 31H07:31 (decimal) Sent from my iPhone > On Mar 31, 2017, at 5:23 AM, Karl Palmen <[hidden email]> wrote: > > Also if the years with a leap month were spread as smoothly as possible, they will naturally form a pattern of 24 19year cycles one of which have an Octaeteris removed. 
Karl, sirs:
>Brij's suggestion is to add 6 months to >each of 23 19year cycles then remove 2 >months. Only the months tally >Months: 23*(235+6)  2 = 5541 I think, this is yet another, confusion! The point I made was for {23*(235+6)2= 5541} Lunations to be counted. Since 19years have 235 moons; six moons are added but ONCE every 3 years  thus making for 23x241=5543 and TWO removed once at [12*241]1; and then at [11*241]1 creating uniform distribution of {2892+2651} =5541 moons; on adding ONE once every 3years in 19year cycle of (235+6) moons! This make {[12*(235+6)1}+{(11*235+6)1}= 5541 moons over 23 19year cycles i.e. (23*241)2 moons smoothly distributed in [19*23.578947367]years or (437*11)years. I expect this make distribution clear, sir. Regards, Brij Bhushan metric VIJ, Author BrijGregorian Modified calendar Friday, 2017 March 31H19:59 (decimal) Sent from my iPhone > On Mar 31, 2017, at 8:32 AM, Karl Palmen <[hidden email]> wrote: > > Dear Brij and Calendar People > > Brij says that has target is the Mean Year and Mean Month, therefore BOTH years and months must be counted. > > One moon removed from (235+6) in 19year cycle etc. does NOT count YEARS. > Also, this has no pattern of YEARS with leap months, because the YEARS are not counted. > > Karl > > 16(08(04 > > Original Message > From: East Carolina University Calendar discussion List [mailto:[hidden email]] On Behalf Of Brij Bhushan metric VIJ > Sent: 31 March 2017 15:19 > To: [hidden email] > Subject: Patterns Re: Short & simple Re: (235+6Adhika) Re: 13th removed from all but 1 in 13 months RE: FORMAT Fwd: ... > > Karl, list sirs: >> Also if the years with a leap month were >spread as smoothly as possible, they will >naturally form a pattern of 24 19year >cycles one of which have an Octaeteris >removed. > I thank you. I, however, leave the choice to astronomers  the need of patternimportance. My target was for Mean Year & Mean Lunation. > One moon removed from (235+6) in 19year cycle; once every 3years also is uniform distribution, I suppose sir. > Regards & thanks, > Brij zbhushan metric VIJ, Author > BrijGregorian Modified calendar > Friday, 2017 March 31H07:31 (decimal) > > Sent from my iPhone > >> On Mar 31, 2017, at 5:23 AM, Karl Palmen <[hidden email]> wrote: >> >> Also if the years with a leap month were spread as smoothly as possible, they will naturally form a pattern of 24 19year cycles one of which have an Octaeteris removed. 
Free forum by Nabble  Edit this page 