Dear Vladimir and Calendar People It looks like the Dominical letters for the years of a Julian 28year cycle, but the dominical letters would have a reverse sequence and the leap years would
have two letters (one for Jan Feb and one for the other months). This I show later on. It seems that the letters correspond to a years beginning with March 1 on a particular day of the week. For the Julian calendar numbering years in AD, the day
of week of March 1 would be as follows: A Tuesday B Wednesday C Thursday D Friday E Saturday F Sunday G Monday If years were numbered differently from AD the letters would probably correspond to different days of the week. It does not work for the Gregorian Calendar because the year begins on January 1^{st} and so leap years would require two letters. If years were modified
to begin March 1, then the days of the week the letters correspond to would depend on the century. For Dominical letters and years beginning January 1 and AD year counting we’d have B A G FE D C B AG F E D CB A G F ED C B A GF E D C BA G F E CD See
http://en.wikipedia.org/wiki/Dominical_letter . Karl 13(08(13 From: East Carolina University Calendar discussion List [mailto:[hidden email]]
On Behalf Of Vladimir Pakhomov This ancient calendar table allows to determine the Julian and Gregorian calendar for any year. Vladimir From: East Carolina University Calendar discussion List [[hidden email]]
On Behalf Of Brij Bhushan Vij Vladimir Pokhomir sir(s): 

This table works for the Gregorian calendar, too. For leap years are not required two letters. A Friday B Saturday C Sunday D Monday E Tuesday F Wednesday G Thursday Calendrical calculations are shown on page http://www.pakhomov.com/calendar.html Vladimir From: East Carolina University Calendar discussion List [mailto:[hidden email]] On Behalf Of Karl Palmen Dear Vladimir and Calendar People It looks like the Dominical letters for the years of a Julian 28year cycle, but the dominical letters would have a reverse sequence and the leap years would have two letters (one for Jan Feb and one for the other months). This I show later on. It seems that the letters correspond to a years beginning with March 1 on a particular day of the week. For the Julian calendar numbering years in AD, the day of week of March 1 would be as follows: A Tuesday B Wednesday C Thursday D Friday E Saturday F Sunday G Monday If years were numbered differently from AD the letters would probably correspond to different days of the week. It does not work for the Gregorian Calendar because the year begins on January 1^{st} and so leap years would require two letters. If years were modified to begin March 1, then the days of the week the letters correspond to would depend on the century. For Dominical letters and years beginning January 1 and AD year counting we’d have B A G FE D C B AG F E D CB A G F ED C B A GF E D C BA G F E CD See http://en.wikipedia.org/wiki/Dominical_letter . Karl 13(08(13 From: East Carolina University Calendar discussion List [[hidden email]] On Behalf Of Vladimir Pakhomov This ancient calendar table allows to determine the Julian and Gregorian calendar for any year. Vladimir 
Dear Vladimir and Calendar People From: East Carolina University Calendar discussion List [mailto:[hidden email]]
On Behalf Of Vladimir Pakhomov This table works for the Gregorian calendar, too. For leap years are not required two letters. A Friday B Saturday C Sunday D Monday E Tuesday F Wednesday G Thursday This table is not valid for all centuries or for January and February in a leap year, unless special provision is made for them. Calendrical calculations are shown on page http://www.pakhomov.com/calendar.html This only uses the Julian calendar March style for which leap years do not require two letters and the table is valid for all centuries. It does not seem to explain, why leap years do not require two letters, for January starting years. Then I thought of a way of making the original Julian calendar table valid for the Gregorian Calendar, but with March starting years. For March 2100 to February 2200, the Julian calendar is exactly two weeks behind and so the same table would work for both calendars then. For each time February 29 is dropped, in a year that is a leap year in the Julian calendar, skip 16 years in the 28year cycle. So for March 1900 to February 2100, one can use the Julian calendar table, but with the 28year cycle running 16 years later or 12 years earlier than in the
Julian calendar. For example 2013 has remainder 28 when divided by 25 so is C in the table, putting March 1 on Thursday. In the Gregorian, the 29year cycle is running 16 years late so it is 9 in the 28year cycle so D in the table, putting March 1 on Friday, as I remember. Karl 13(08(14 Vladimir From: East Carolina University Calendar discussion List [[hidden email]]
On Behalf Of Karl Palmen Dear Vladimir and Calendar People It looks like the Dominical letters for the years of a Julian 28year cycle, but the dominical letters would have a reverse sequence and the leap years would
have two letters (one for Jan Feb and one for the other months). This I show later on. It seems that the letters correspond to a years beginning with March 1 on a particular day of the week. For the Julian calendar numbering years in AD, the day
of week of March 1 would be as follows: A Tuesday B Wednesday C Thursday D Friday E Saturday F Sunday G Monday If years were numbered differently from AD the letters would probably correspond to different days of the week. It does not work for the Gregorian Calendar because the year begins on January 1^{st} and so leap years would require two letters. If years were modified
to begin March 1, then the days of the week the letters correspond to would depend on the century. For Dominical letters and years beginning January 1 and AD year counting we’d have B A G FE D C B AG F E D CB A G F ED C B A GF E D C BA G F E CD See
http://en.wikipedia.org/wiki/Dominical_letter . Karl 13(08(13 From: East Carolina University Calendar discussion List [[hidden email]]
On Behalf Of Vladimir Pakhomov This ancient calendar table allows to determine the Julian and Gregorian calendar for any year. Vladimir 

Karl, you are wrong. March 1, 2013 of the Julian calendar was Thursday. OK. March 1, 2013 of the Julian calendar corresponds to March 14, 2013 of the Gregorian calendar (1+13=14). Therefore, March 14, 2013 of the Gregorian calendar was Thursday. Check it out! If you have determined the day of the week for March 14, 2013 of the Gregorian calendar, so you have determined the Gregorian calendar for 2013. See "The Calendar Calculations" on webpage http://www.pakhomov.com/calendar.html Vladimir From: East Carolina University Calendar discussion List [mailto:[hidden email]] On Behalf Of Karl Palmen Dear Vladimir and Calendar People From: East Carolina University Calendar discussion List [[hidden email]] On Behalf Of Vladimir Pakhomov This table works for the Gregorian calendar, too. For leap years are not required two letters. A Friday B Saturday C Sunday D Monday E Tuesday F Wednesday G Thursday This table is not valid for all centuries or for January and February in a leap year, unless special provision is made for them. Calendrical calculations are shown on page http://www.pakhomov.com/calendar.html This only uses the Julian calendar March style for which leap years do not require two letters and the table is valid for all centuries. It does not seem to explain, why leap years do not require two letters, for January starting years. Then I thought of a way of making the original Julian calendar table valid for the Gregorian Calendar, but with March starting years. For March 2100 to February 2200, the Julian calendar is exactly two weeks behind and so the same table would work for both calendars then. For each time February 29 is dropped, in a year that is a leap year in the Julian calendar, skip 16 years in the 28year cycle. So for March 1900 to February 2100, one can use the Julian calendar table, but with the 28year cycle running 16 years later or 12 years earlier than in the Julian calendar. For example 2013 has remainder 28 when divided by 25 so is C in the table, putting March 1 on Thursday. In the Gregorian, the 29year cycle is running 16 years late so it is 9 in the 28year cycle so D in the table, putting March 1 on Friday, as I remember. Karl 13(08(14 Vladimir From: East Carolina University Calendar discussion List [[hidden email]] On Behalf Of Karl Palmen Dear Vladimir and Calendar People It looks like the Dominical letters for the years of a Julian 28year cycle, but the dominical letters would have a reverse sequence and the leap years would have two letters (one for Jan Feb and one for the other months). This I show later on. It seems that the letters correspond to a years beginning with March 1 on a particular day of the week. For the Julian calendar numbering years in AD, the day of week of March 1 would be as follows: A Tuesday B Wednesday C Thursday D Friday E Saturday F Sunday G Monday If years were numbered differently from AD the letters would probably correspond to different days of the week. It does not work for the Gregorian Calendar because the year begins on January 1^{st} and so leap years would require two letters. If years were modified to begin March 1, then the days of the week the letters correspond to would depend on the century. For Dominical letters and years beginning January 1 and AD year counting we’d have B A G FE D C B AG F E D CB A G F ED C B A GF E D C BA G F E CD See http://en.wikipedia.org/wiki/Dominical_letter . Karl 13(08(13 From: East Carolina University Calendar discussion List [[hidden email]] On Behalf Of Vladimir Pakhomov This ancient calendar table allows to determine the Julian and Gregorian calendar for any year. Vladimir  
Vladimir, Karl sirs:
>.....March 14, 2013 of the Gregorian calendar was Thursday. Check it out! YES, it was a Thursday at MJD 2,456,366, and March 1, 2013 of the Julian calendar. Again, MJD 2,456,364 was a DARK MOON, on Tuesday March 12, 2013. BUT, are we adding any newer knowledge to calendarreform! >See "The Calendar Calculations" on webpage: http://www.pakhomov.com/calendar.html ONE day error in 128years is not expalined?? May I point that there is ONE day error between Julian & Gregorian calendars in 3200years as shown by my 'several inputs/mails discussed with listserv. Regards, Brij Bhushan VijThursday, 2013 April 25H17:07(decimal)EST Aa Nau Bhadra Kritvo Yantu Vishwatah Rg Veda The Astronomical Poem (revised number of days in any month) "30 days has July,September, April, June, November and December all the rest have 31 except February which has 29 except on years divisible evenly by 4; except when YEAR divisible by 128 and 3200  as long as you remember that "October (meaning 8) is the 10th month; and December (meaning 10) is the 12th BUT has 30 days & ONE OUTSIDE of calendarformat" Jan:31; Feb:29; Mar:31; Apr:30; May:31; Jun:30 Jul:30; Aug:31; Sep:30; Oct:31; Nov:30; Dec:30 (365th day of Year is World Day) ******As per Kali VGRhymeCalendaar***** "Koi bhi cheshtha vayarth nahin hoti, purshaarth karne mein hai" My Profile  http://www.brijvij.com/bbv_2colvipBrief.pdf Author had NO interaction with The World Calendar Association except via Media & Organisations to who I contributed for A Possible World Calendar, since 1971. HOME PAGE: http://www.brijvij.com/ Contact via Email: [hidden email] OR "GAYATRI LOK" Flat # 3013/3rd Floor NH58, Kankhal Bypass, DevBhoomi, HARIDWAR249408 (Uttrakhand  INDIA) Date: Thu, 25 Apr 2013 10:21:36 +0400 From: [hidden email] Subject: Re: Ancient Calendar Table RE: ... RE: Sliding and table calendars To: [hidden email] Karl, you are wrong. March 1, 2013 of the Julian calendar was Thursday. OK. March 1, 2013 of the Julian calendar corresponds to March 14, 2013 of the Gregorian calendar (1+13=14). Therefore, March 14, 2013 of the Gregorian calendar was Thursday. Check it out! If you have determined the day of the week for March 14, 2013 of the Gregorian calendar, so you have determined the Gregorian calendar for 2013. See "The Calendar Calculations" on webpage http://www.pakhomov.com/calendar.html
Vladimir
From: East Carolina University Calendar discussion List [mailto:[hidden email]] On Behalf Of Karl Palmen
Dear Vladimir and Calendar People
From: East Carolina University Calendar discussion List [[hidden email]] On Behalf Of Vladimir Pakhomov
This table works for the Gregorian calendar, too. For leap years are not required two letters.
A Friday B Saturday C Sunday D Monday E Tuesday F Wednesday G Thursday
This table is not valid for all centuries or for January and February in a leap year, unless special provision is made for them.
Calendrical calculations are shown on page http://www.pakhomov.com/calendar.html This only uses the Julian calendar March style for which leap years do not require two letters and the table is valid for all centuries. It does not seem to explain, why leap years do not require two letters, for January starting years.
Then I thought of a way of making the original Julian calendar table valid for the Gregorian Calendar, but with March starting years. For March 2100 to February 2200, the Julian calendar is exactly two weeks behind and so the same table would work for both calendars then. For each time February 29 is dropped, in a year that is a leap year in the Julian calendar, skip 16 years in the 28year cycle. So for March 1900 to February 2100, one can use the Julian calendar table, but with the 28year cycle running 16 years later or 12 years earlier than in the Julian calendar.
For example 2013 has remainder 28 when divided by 25 so is C in the table, putting March 1 on Thursday. In the Gregorian, the 29year cycle is running 16 years late so it is 9 in the 28year cycle so D in the table, putting March 1 on Friday, as I remember.
Karl
13(08(14
Vladimir
From: East Carolina University Calendar discussion List [[hidden email]] On Behalf Of Karl Palmen
Dear Vladimir and Calendar People
It looks like the Dominical letters for the years of a Julian 28year cycle, but the dominical letters would have a reverse sequence and the leap years would have two letters (one for Jan Feb and one for the other months). This I show later on.
It seems that the letters correspond to a years beginning with March 1 on a particular day of the week. For the Julian calendar numbering years in AD, the day of week of March 1 would be as follows: A Tuesday B Wednesday C Thursday D Friday E Saturday F Sunday G Monday If years were numbered differently from AD the letters would probably correspond to different days of the week.
It does not work for the Gregorian Calendar because the year begins on January 1^{st} and so leap years would require two letters. If years were modified to begin March 1, then the days of the week the letters correspond to would depend on the century.
For Dominical letters and years beginning January 1 and AD year counting we’d have
B A G FE D C B AG F E D CB A G F ED C B A GF E D C BA G F E CD
See http://en.wikipedia.org/wiki/Dominical_letter .
Karl
13(08(13
From: East Carolina University Calendar discussion List [[hidden email]] On Behalf Of Vladimir Pakhomov
This ancient calendar table allows to determine the Julian and Gregorian calendar for any year.
Vladimir
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