Dear Brij and Calendar People I do remember exploring the idea of converting a solar calendar into a lunar calendar by removing the 13^{th} day of each month and possibly adding
leap months to make it lunisolar. The most interesting result of this exploration was that if we add leap months of 31 days from which the 13^{th} is normally removed, about 1 in 13 months must keep
the 13^{th} and this is exact for the 391year cycle of 144 leap months. In any such case there must be exactly 31 months that have no 13^{th} for each leap month, so that the lunisolar calendar does not drift against the
solar calendar, which has no 13^{th}s removed and no leap months. So the 391year cycle has 31*144 months with the 13^{th} removed and hence 12*391 + 144 – 31*144 = 12*391 – 30*144 = 372 months keep the 13^{th}.
The 391year cycle has 391*12 + 144 = 4836 = 13*372 months, so this 372 is exactly 1 in 13 months. Brij’s 896year cycle of 11082 months has 11082 – 12*896 = 330 leap months and so 10230 months have a 13^{th} removed and so 11082 – 10230 = 852 month
keep the 13^{th}. This works out is 1 in 13.00704… months. For the more accurate 334year cycle we get 4131 – 31*123 = 318 months that keep the 13^{th}, which is 1 in 12.99057… months. For the 19year Metonic cycle, 235 – 7*31 = 18 months keep the 13^{th} and in the truncated 11year Metonic cycle, 136 – 4*31 = 12 months keep the 13^{th}
. Hence in general, the number of months that keep the 13^{th} is equal to the number of years less the number of saltus lunae corrections, which is listed in my lunisolar spreadsheets. http://thelight.com/cal/kp_Lunisolar_xls.html
Karl 16(08(02 From: East Carolina University Calendar discussion List [mailto:[hidden email]]
On Behalf Of Brij Bhushan metric VIJ Walter, Karl list, sirs: This format of my Harappa TithiLunar calendar was discussed during my proposed 'Tithi value of 966days/965 published and compared with several other values: 2L/59, 1/30, 1/29, 138w/965 and later fixed at 1+338/326919 day. It's simplicity
as desired was arrived at: One Tithi= No.of days in 896years/No. of 'tithi' in (11082 moons x 29 1/2 tithi) i.e. 327257/326919 day falling short of 1 Tithi "added as Adhika in 11082nd moon" making this a perfect lunisolar combination of my 896years. The format had been projected during my mails for 'count of solar days' by removing the 13th Day of every Gregorian month, as reproduced: as the possible 30,29 day (two lunations having 59Tithi)  to result in 354Tithi in a synodic month. Current year Y2017 is 97th after {(Y2000 +/80) div.128=Y1920}. This is 23747 moons from Y0000, for using Gregorian names of months (as an alternate to current regional names of seasons matching with moon position). 896year cycle is "2 x 448years", each with 5541moons. The format is a part in my compendium as "OUTPUT of Research & Contributions  1971..... a Surest, Easiest & Cheapest way out. There may be (461x12)+913th added month= 5541) moons in 448years. Regards, Brij Bhushan metric VIJ Author, BrijGregorian Modified calendar Tuesday, 2017 March 28H20:16 (decimal) Sent from my iPhone

Dear Karl, list sirs:
>Brij’s 896year cycle of 11082 months has ><a href="tel:11082%20%2012" dir="ltr" xappledatadetectors="true" xappledatadetectorstype="telephone" xappledatadetectorsresult="0">11082 – 12*896
= 330 leap months and so >10230 months have a 13^{th} removed and so ><a href="tel:11082%20%2010230" dir="ltr" xappledatadetectors="true" xappledatadetectorstype="telephone" xappledatadetectorsresult="1">11082 – 10230 = 852 month keep
the 13^{th}. >This works out is 1 in 13.00704… months. >For the more accurate 334year cycle we >get 4131 – 31*123 = 318 months that keep >the 13^{th}, which is 1 in 12.99057… months.
I thank you, and the list for reelavuating my calculations; but I stand put with my 'tithi' value of: No.of days in 896/years/No.of Tithi in (11082x29 1/2) or 326919=1 338/326919 day. This fits
in 896years, 834years & my 19years 'harappatithi' cycles.
"896years have 327257 days in 11082 moons but ONE day/Tithi of 1 338/326819 day short. Adding 'this' ONE
added/ 'Adhika day' in the cycle result in Mean Lunation={(327257+1)/ 326919) =29.530590146183 days} i.e.29d 12h 44m 2s.9887.
This cycle may have (2x448)years of (2x5541) moons; accounted as [(12*241) 1]+[(11*241)1]= 2891+2650= 5541 moons to give the right (above) Mean Lunation. The ERA may start at the beginning of Kali Era on 3102BCE making the year, Y2018=5120th or the last year of (40th*128year) cycles. This may be Noted, that 19years have 235 moons BUT adding "six(6) Kshamoons to be deleted ONCE every 3years " make the required (2416= 235) moons per 19year cycle. Thus, [(12*241)1+(11*241)1]; are {(2x5543)2} ie (23x241) moons per 448years [23*241 =5543 lunation]. This produces Mean Lunation of 29d 12h 44m 2s.9887 in comparison to the current moon duration. Regards, Brij Bhushan metric VIJ, Author, BrijGregorian Modified calendar Wednesday, 2017 March 29H14:11 (decimal)
Sent from my iPhone

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